On 09/12/2007, Ken B. [email protected] wrote:
until looplets.empty?puts
p
mm
(The last is a testcase which makes sure that I get the #shifts and #pops
right)
I thought this one is too easy once you understand what it is about
but people always come up with difficult solutions. I wish I knew what
the regexp does :S
For those who cannot understand it either:
def indexes l, i
res = []
ptr = 0
while (ptr = l.index i, ptr)
res << ptr
ptr+=1
end
res
end
.
#.c1=c5…c2
. .
c4…c3
def draw_loop word, c1, c5
length = (c5 - c1) -4
width = length/4
height = length/2 - width
word = word[0…0].upcase + word[1…-1]
c2 = c1 + width +1
c3 = c2 + height +1
c4 = c3 + width +1
word[(c5+1)…-1].reverse.scan(/./).map{|c| " "*c1 + c + “\n”}.join +
word[0…c2] + “\n” +
(1…height).map{|i| " "*c1 + word[c5 - i].chr + " "*width +
word[c2 + i].chr + “\n”}.join +
" "*c1 + word[c3…c4].reverse + “\n”
end
def wloop word
word=word.downcase
tried=[]
ptr=0
while ptr < word.length
if tried.include? word[ptr]
ptr+=1
next
end
char = word[ptr]
tried << char
pos = indexes word, char
next unless pos.length > 1
i, j = 0
while i < pos.length - 1
j=pos.length - 1
while j > i
diff = pos[j] - pos[i]
if (diff)>=4 && (diff) % 2 == 0
return draw_loop word, pos[i], pos[j]
end
j-=1
end
i+=1
end
ptr += 1
end
“No loop \n”
end
