how to convert a “%d/%m/%Y” date to a “%Y/%m/%d” date?
if it’s a string then use the the split function. split it up by
the /. It should return 3 values after being split… the day, the
month, and the year. Then rearrange them.
Ben L. wrote:
if it’s a string then use the the split function. split it up by
the /. It should return 3 values after being split… the day, the
month, and the year. Then rearrange them.
or you can just use date_object.strftime("%Y/%m/%d")
and that should do the trick.
cheers,
s