Need help reading a yaml file on upload with form

Rails
1

Here is the current basic information:

new (views/file_uploads/new.html.erb)

<% form_for( @file_upload, :html => { :multipart => true } ) do |f| %>
<%= f.error_messages -%>

<%= f.label :upload, 'File' -%> <%= f.file_field :upload -%>

<%= f.submit( 'Upload' ) %>

<% end %>

controller

def new
@file_upload = FileUpload.new
end

def create
@theme_upload = FileUpload.new(params[:upload])

respond_to do |format|
if FileUpload.save
flash[:notice] = ‘Successfully Uploaded File.’
format.html { redirect_to(@file_upload) }
else
format.html { render :action => “new” }
end
end
end

model

class FileUpload < ActiveRecord::Base

validates_presence_of :upload
attr_accessor :upload

end

yaml file being uploaded

file:
name: default
author: First L.
date: 2010-01-01
stylesheets: true
javascripts: true
layouts: true
swfs: true

=================

What I would like to be able to do is eventually upload a number of file
folders with files based off what is listed in a YAML file being
selected and read.

For instance, if I could info = YAML.load_file(the_path_to_upload_file)
I would get the following:

=> {“file”=>{“name”=>“default”, “date”=>Fri, 01 Jan 2010,
“author”=>“First L.”, “swfs”=>true, “javascripts”=>true,
“layouts”=>true, “stylesheets”=>true}}

and would be able to read/use the information later on.

My problem is understanding how to call/access that information using
the template above. If I run it right now, of course what will happen
is a record will be saved with nil information because nothing is truly
being sent/saved properly.

However, when viewing it in the console, the following information is
being sent via parameters:

Parameters: {“commit”=>“Upload”,
“authenticity_token”=>“4IW8zdd8WyHFBjxMJgxZbPtPp0XlJiPInxtlywfaf74=”,
“file_upload”=>{“upload”=>#<File:C:/Users/MyUser/AppData/Local/Temp/RackMultipart.3076.2>}}

If I open the Rackmultipart.3076.2 file it does match the exact same
contents of the yaml file being uploaded.

Again, I’m unsure of how to go about defining a method to simply read
the yaml file and parse its contents using an upload button.

2

For instructional use here is what I see:

  1. Admin user goes to form.
  2. Admin user selects browse and finds the yaml file.
  3. Admin users selects upload.
  4. yaml file is read and parsed.
  5. model saves the information from the yaml file into a record.
  6. uploading begins in another routine based off what was recorded in
    step 5.

I hope that helps…

My problem is understanding what to do between steps 3 - 5.

3

On Jan 12, 1:47Â pm, Alpha B. [email protected] wrote:

Â

<%= f.submit( ‘Upload’ ) %>

model

file:
What I would like to be able to do is eventually upload a number of file
and would be able to read/use the information later on.
“authenticity_token”=>“4IW8zdd8WyHFBjxMJgxZbPtPp0XlJiPInxtlywfaf74=”,
“file_upload”=>{“upload”=>#<File:C:/Users/MyUser/AppData/Local/Temp/RackMul tipart.3076.2>}}

If I open the Rackmultipart.3076.2 file it does match the exact same
contents of the yaml file being uploaded.

Again, I’m unsure of how to go about defining a method to simply read
the yaml file and parse its contents using an upload button.

Posted viahttp://www.ruby-forum.com/.

Are you looking for local_path?

As in YAML.load_file params[:file_upload][:upload].local_path
?

4

pharrington wrote:

Are you looking for local_path?

As in YAML.load_file params[:file_upload][:upload].local_path
?

Thanks mate - yes this is exactly what I was looking for. I have not
done a lot of work with reading files and am becoming familiar with how
to do certain things with them. I couldn’t figure out how to translate
the local_path and now you showed me.

Many thanks!