Problems loading yaml file with Rake

Ruby Development
1

Hi,
I have problems loading a yaml file with Rake when testing and getting the following error;
Errno::ENOENT: No such file or directory @ rb_sysopen
But there are no problems when testing from within the test directory. The Rakefile is located at the root of the project.

2

Hard to say without seeing your rakefile, but my first guess would be a path problem. When you try to load the yaml file, does rake know its location? e.g. if it is in the test directory?

3

Rakefile content in test directory:

require ā€˜rake/testtaskā€™

task :default => :test

Rake::TestTask.new do |task|
task.pattern = ā€˜test_*.rbā€™
task.warning = true
end

No problems loading yaml file.

Moving Rakefile to root directory of project:

require ā€˜rake/testtaskā€™

task :default => :test

Rake::TestTask.new do |task|
task.pattern = ā€˜lib/language_quiz/test_*.rbā€™
task.warning = true
end

4

continued:

Errno::ENOENT: No such file or directory @ rb_sysopen

5

This does not mention the yaml file.

Where is the yaml file being loaded? and how?

Remember that the ā€˜base folderā€™ that files are searched on will change depending on where you run the Rakefile from.

6

All files, including the yaml file are lying in the same directory(language_quiz) for now. The yaml file is loaded via a quiz-class in a quiz.rb file through its initializer i.e @data = YAML.load(File.read(ā€œpath to yaml fileā€))

7

I donā€™t know if this helps;
But if I put the load path to the yaml file in the quiz.rb file relative to where the rake file is, ā€œthe base folderā€, then it finds it.

class Quiz(in quiz.rb)
.
.
.

def initialize
begin
$LOG.debug(ā€œTest loading yaml dataā€¦ā€)
@data = YAML.load(File.read(ā€œpath to yaml file relative to the rakefile in the base folderā€))
end
.
.
.

end

But then I canā€™t run the test from within the ā€œlanguage_quizā€ folder properly where I find the quiz.rb and the test_quiz.rb file

8

Probably your best solution is to find the directory of the file in which you are loading the file, e.g. by:

CWD = File.expand_path(File.dirname(__FILE__))

Then you can write:

YAML.load(File.read(File.join(CWD, 'yaml-file')))

You can then name the ā€˜yaml-fileā€™ relative to the file in which the call is.

1 Like
9

That did it! Great! Thanks! :smiley: